What Makes Trump & #MAGA So #Cruel? A #Psychiatrist Explains
https://www.youtube.com/watch?v=4T8jF8BEeCM
#evil #godless #mean #cruelty #TACO
What Makes Trump & #MAGA So #Cruel? A #Psychiatrist Explains
https://www.youtube.com/watch?v=4T8jF8BEeCM
#evil #godless #mean #cruelty #TACO
Thank goodness for small mercies. While the #budget bill is #ugly and #mean spirited and actually increases our #debt as per #CBO, even small wins like this matter. Keep our #public lands safe.
#BLM #UtahPolitics #Utah #government #sellout #corruption #corruptGOP #USPolitics
https://utahnewsdispatch.com/2025/05/22/celeste-maloy-utah-public-land-sale/
Japan ‘bumping gang’ deliberately collides with pedestrians, mostly women, to vent frustrations https://www.byteseu.com/1019928/ #angry #Britain #bumping #BumpingGang #DaisukeNagata #frustrations #gang #Gender #GenderBias #harassment #Japan #japanese #jealous #london #March #May2018 #mean #nasty #outrage #Pedestrians #SallyWynter #SocialMedia #Subway #Tokyo #TrainStations #venting #victims #women
Wendy’s NZ expansion planned under new US giant Flynn Group’s ownership https://www.byteseu.com/952584/ #about #business #Expansion #FAST #flynn #Food #giant #group #groups #local #mean #midlast #new #NewZealand #NZ #operations #ownership #planned #plenty #sold #speculation #there #under #US #wendys #were #What #when #would #year #zealand
#mean : common; low; vulgar; humble
- French: mauvaise
- German: meinen
- Portuguese: significa, malvado
- Spanish: malo
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Something I made for my intro stats class a few years ago. Nobody really appreciated it, which is a tragedy because it's absolutely top-notch humor.
In a magazine article [1] on problems and progress in quantum field theory, Wood writes of Feynman path integrals, “No known mathematical procedure can meaningfully average an infinite number of objects covering an infinite expanse of space in general. The path integral is more of a physics philosophy than an exact mathematical recipe.”
This article [2] provides a method for averaging an arbitrary collection of objects; however, the average can be any number in the extension of the range of these objects. (Note, an arbitrary collection of these objects is a function.)
Question: Suppose anything meaningful has applications in quantum field theory. Is there a way to meaningfully choose a unique, finite average of a function whose graph matches the description in Wood's quote?
For more info, see this post [3].
Otoboke Beaver おとぼけビ~バ~ // #OtobokeBeaver #おとぼけビーバー //
Itekoma Hits いてこまヒッツ
[album, 2019]
//via // #Damnably //
#brandunbrand #music #bandcamp #ItekomaHits #いてこまヒッツ #DatsuHikageNoOnna #Akimahenka #SilVousPlait #BakuroBook #WhatDoYouMeanYouHaveTalkToMeAtThisLateHour? #IntroduceMeToYourFamily #LoveIsShort #BadLuck #DontLightMyFire #6DayWorkWeekIsAPain #BingeEatingBingeDrinkingBulimia #ImTiredOfYourRepeatingStory #AnataWatashiDaitaAtoYomeNoMeshi #Mean
link bandcamp: https://otobokebeaver.bandcamp.com/album/itekoma-hits
Intuitive Explanation of Arithmetic, Geometric & Harmonic Mean - The simple definition of a mean is that of a numeric quantity which represents the... - https://hackaday.com/2024/08/24/intuitive-explanation-of-arithmetic-geometric-harmonic-mean/ #statistics #science #mean
I’m thinking of getting into being extremely #mean. Any #malignant #rude #disagreeable #hurtful scoundrels out there got any tips on how to start?
Question 1. was solved here [1]. The answer isn't perfect but it's better than nothing.
I don't know if the function in the answer to this post [1] has a finite expected value using section 3.2 and 6.1 of this paper [2].
Suppose \(A\subseteq\mathbb{R}^{2}\) is Borel and \(B\) is a rectangle of \(\mathbb{R}^2\). In addition, suppose the Lebesgue measure on the Borel \(\sigma\)-algebra is \(\lambda(\cdot)\):
Question: How do we define an explicit \(A\), such that:
1. \(\lambda(A\cap B)>0\) for all \(B\)
2. \(\lambda(A\cap B)\neq\lambda(B)\) for all \(B\)?
For a potential answer, see this reddit post [1]. (It seems the answer is correct; however, I wonder if there's a simpler version that is less annoying to prove.)
Moreover, we meaningfully average \(A\) with the following approach:
Approach: We want an unique, satisfying extension of the expected value of \(A\), w.r.t the Hausdorff measure in its dimension, on bounded sets to \(A\), which takes finite values only
Question 2: How do we define "satisfying" in this approach?
(Optional: See section 3.2, & 6 of this paper [2].)
Suppose \(f:\mathbb{R}\to\mathbb{R}\) is Borel. Let \(\text{dim}_{\text{H}}(\cdot)\) be the Hausdorff dimension and \(\mathcal{H}^{\text{dim}_{\text{H}}(\cdot)}(\cdot)\) be the Hausdorff measure in its dimension on the Borel \(\sigma\)-algebra.
Question: If \(G\) is the graph of \(f\), is there an explicit \(f\) such that:
1. The function \(f\) is everywhere surjective (i.e., \(f[(a,b)]=\mathbb{R}\) for all non-empty open interval \((a,b)\))
2. \(\mathcal{H}^{\text{dim}_{\text{H}}(G)}(G)=0\)
If such \(f\) exists, we denote this special case of \(f\) as \(F\).
Note, not all everywhere surjective \(f\) satisfy criteria 2. of the question. For example, consider the Conway base-13 function [1]. Since it's zero almost everywhere, \(\text{dim}_{\text{H}}(G)=1\), and \(\mathcal{H}^{\text{dim}_{\text{H}}(G)}(G)=+\infty\).
Question 2: For any real \(\mathbf{A},\mathbf{B}\) is the expected value of \(\left.f\right|_{[\mathbf{A},\mathbf{B}]}\), w.r.t the Hausdorff measure in its dimension, defined and finite?
If not, see this paper [2] for a partial solution.
Optional: Is there other interesting properties of \(F\)?
A young Maureen O'Hara inflicting pain, and loving every second of it:
"An unkind remark is like a killing frost - no matter how much it warms up, the damage is already done." — Suzanne Woods Fisher — — — #SuzanneWoodsFisher #quote #quotes #unkind #mean #remark #damage #lasting #criticism #criticize #burtful
20240619 #2 15.34 WIB
171/366 Days 12,481
Udah pengen ditabok belum?
#JustForFun #Tiktok #Reels #Mean #OMg #TowerKemuning #Jakarta #Indonesia #Wednesday #June #19th #2024
#SouthDakota #Governor #KristiNoem Reportedly describes committing #animalcruelty shooting a 14 month old #puppy named #Cricket in New #Book: ‘I #Hated That #Dog’, ‘HAD TO BE DONE’
She then proceeded talk about how she also killed a “#nasty and #mean” #goat, according to a copy of the forthcoming #book obtained by The Guardian.
#Women #Transgender #LGBTQ #LGBTQIA #AnimalCruelty #Conservatives #Extremism #Fascism #RepublicanParty #ThePartyOfHate